The constituents of the essential oil of American pennyroyal / by Marmaduke Barrowcliff.
- Barrowcliff, Marmaduke.
- Date:
- 1907
Licence: In copyright
Credit: The constituents of the essential oil of American pennyroyal / by Marmaduke Barrowcliff. Source: Wellcome Collection.
Provider: This material has been provided by The Royal College of Surgeons of England. The original may be consulted at The Royal College of Surgeons of England.
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![Fraction 240—250°—The amount of this fraction was only 3 grams : 0-1008 gave 0-2935 COg and 0-0978 HgO. C = 79-8 ; H = 10-8. d 20°/20° =0-9296; + 4°56' in a 1-dcm. tube. Fraction 250—260°.—This amounted to 3 grams : 0-1173 gave 0-3415 CO2 and 0-1145 HgO. C = 79-4; H=10'8. d 20°/20° =0-9302; ao - 0°24' in a 1-dcm. tube. Fraction 260—270°.—This amounted to 3 grams : 0-1100 gave 0-3163 CO2 and 0-1067 H2O. C = 78-4; H=10-8. d 20°/20° =0-9322; od -p0°12' in a 1-dcm. tube. Fraction 270—280°.—This amounted to 3 grams : 0-1289 gave 0-3717 CO2 and 0-1245 HgO. 0 = 78-6 ; H = 10-7. d 20°j20° =0-9385; -h 1°56' in a 1-dcm. tube. Fraction 280—290°.—This amounted to 3 grams : 0-1090 gave 0-3121 CO2 and 0-1055 HgO. C = 78-1; H = 10-7. d 20°/20° =0-9375 ; Co +4°56' in a 1-dcm. tube. As the five preceding fractions were all so very small in amount, they were not further examined. Fraction 290—300°.—The amount of this fraction was 8 grams : 0-1099 gave 0-3187 CO2 and 0-1092 HgO. C = 79-l ; H = ll-0. d 20°/20° =0-9307; aj, -|-9°32' in a 1-dcm. tube. The characters of this fraction indicated it to consist of a mixture of the constituents of the preceding and the following fractions. Fraction 300—310°.—The amount of this fraction was 7 grams : 0-1150 gave 0-3375 CO2 and 0-1151 H2O. C = 80-0; H = 1M. CijHggO requires C = 81-l; H=11'7 per cent. d 20°/20° =0-9259 ; [a]n + 12°48' in a 1-dcm. tube. The analysis and boiling point of this fx-action indicated that it might contain a sesquiterpene alcohol, and as it was impossible to obtain the latter in a state of purity, it was deemed of interest to prepare the corresponding sesquiterpene from it. The entire fraction was accordingly distilled several times over phosphoric oxide, and then twice over metallic sodium under 60 mm. pressure, when it finally passed over between 160° and 170°. Under the ordinary pressure it distilled between 270° and 280° : 0-0890 gave 0-2872 CO2 and 0-0916 H2O. C = 88-0 ; H = 11 -4. C15H24 requires C = 88-2 ; H = 11 -8 per cent. d 20°/20° =0-8981 ; -I-1°4' in a 1-dcm. tube ; =1-5001. Molecular refraction, 66-80. The value obtained for the piolecul;xr pefractiop indicates tlxat this](https://iiif.wellcomecollection.org/image/b22425068_0015.jp2/full/800%2C/0/default.jpg)