On the utilisation of the water of condensation from steam pipes and cylinders / by Peter Fyfe.
- Fyfe, Peter.
- Date:
- 1890
Licence: Public Domain Mark
Credit: On the utilisation of the water of condensation from steam pipes and cylinders / by Peter Fyfe. Source: Wellcome Collection.
Provider: This material has been provided by The University of Glasgow Library. The original may be consulted at The University of Glasgow Library.
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![pipes under 12 diameter, the radiation per square foot of surface exposed is not constant. It varies in an arithmetical ratio inversely as the square of the diameter. So that we see small pipes radiate more per superficial unit of surface than larger ones up to 12 diameter. Above this diameter it has been found that radiation is directly as the surface exposed. In investigating the amount of condensation iu cubic feet of .steam, which takes place in steam pipes, there are two facts which must be discovered—• 1-—The units of heat radiated per hour. 2.—The latent heat per cubic foot of the steam in the pipes. When these are found, the former divided by the latter gives the condensation per hour of steam in cubic feet. All large drying stoves when heated by steam have to be brought up to a required temperature gradually, so that for the first 40 or 60 minutes the same formula which applies to uncovered steam pipes in a factory, exposed to the surrounding atmosphere, applies during the first hour or so to them, so far as their power of conden.sing steam is concerned. So for the first hour, let us see what our drying stove at Belvidere is capable of condensing— Let L = The length of piping in feet, = 4401 feet. „ / = The diameter of pipes in inches, =2*25 inches. „ T = The temperature of steam in pipes, = 269° (25 lbs. pres.). „ t = The temperature of air, = 40° at start. „ A = No. of heat units radiated per hour. ,, c ;= Cubic feet of steam at T condensed per hour. „ H = Latent heat per cubic foot of steam, = 88-14. „ X = Exponent for draught of air in stove, = 1-2 (calm). h will be found by the formula. ^- = 34M^ ['^^0 + (12 - 0^] {r-tf. Or, in figures, , 4401 X 2-25 r ~1 = :34Q4-8 L^^^ + - 2-25)2j (269 - 40)l-2](https://iiif.wellcomecollection.org/image/b21459678_0004.jp2/full/800%2C/0/default.jpg)